Hcf
Mon 21 July 2025
# created :20250629
https://share.google/camtfs4z8aiYAJNSz
def compute_hcf(x, y):
if x > y:
smaller = y
else:
smaller = x
for i in range(1, smaller+1):
if((x % i == 0) and (y % i == 0)):
hcf = i
return hcf
num1 = 54
num2 = 24
print("The H.C.F. is", compute_hcf(num1, num2))
Score: 5
Category: basics