Hcf

Mon 21 July 2025
# created :20250629
https://share.google/camtfs4z8aiYAJNSz
def compute_hcf(x, y):
    if x > y:
        smaller = y
    else:
        smaller = x
for i in range(1, smaller+1):
        if((x % i == 0) and (y % i == 0)):
            hcf = i 
    return hcf
num1 = 54 
num2 = 24
print("The H.C.F. is", compute_hcf(num1, num2))

Score: 5

Category: basics